<\/span>Ti\u1ec1n l\u00e3i s\u1ed1 \u0111\u00e1 3 trong v\u00e0i tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3<\/h3>\n\u0110\u00e1 l\u00f4 3 t\u1ee9c l\u00e0 ng\u01b0\u1eddi ch\u01a1i ch\u1ecdn ra 3 con s\u1ed1, 3 con s\u1ed1 n\u00e0y s\u1ebd t\u1ea1o th\u00e0nh 3 c\u1eb7p s\u1ed1 (3 v\u00f2ng d\u1ef1 th\u01b0\u1edfng).<\/p>\n
VD: S\u1ed1 \u0111\u00e1 3 con l\u00f4 12 23 34 t\u1ea1o th\u00e0nh 3 c\u1eb7p 12-23; 23-34; 34-12 (3 v\u00f2ng)<\/p>\n
Ch\u01a1i s\u1ed1 \u0111\u00e1 3 con, n\u1ebfu v\u1ec1 2 con s\u1ed1 (v\u1ec1 1 c\u1eb7p l\u00f4) th\u00ec m\u1edbi xem l\u00e0 tr\u00fang s\u1ed1 \u0111\u00e1. C\u00e1c tr\u01b0\u1eddng h\u1ee3p tr\u00fang \u0111\u01b0\u1ee3c chia c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
Tr\u00fang 2 tr\u00ean t\u1ed5ng 3 s\u1ed1 (tr\u00fang 1 c\u1eb7p): ti\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 2.
\n48 * 12.5 = 600k<\/p>\n
Tr\u00fang 2 s\u1ed1 v\u00e0 c\u00f3 1 s\u1ed1 v\u1ec1 2 nh\u00e1y. VD: \u0111\u00e1nh 11 22 33 v\u00e0 v\u1ec1 11; 22 v\u1ec1 2 nh\u00e1y, 33 c\u00e2m.
\nTi\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh th\u00eam n\u1eeda v\u00f2ng, t\u1ee9c l\u00e0 ti\u1ec1n x\u00e1c 1 c\u1eb7p l\u00f4 nh\u00e2n t\u1ef7 l\u1ec7 \u0103n c\u01b0a \u0111\u00f4i.
\n48 * 12.5 \/ 2 = 300k<\/p>\n
Tr\u00fang 2 s\u1ed1, trong \u0111\u00f3 c\u00f3 1 s\u1ed1 v\u1ec1 3 nh\u00e1y. VD: v\u1ec1 11 v\u00e0 22 v\u1ec1 3 nh\u00e1y, 33 kh\u00f4ng v\u1ec1.
\nTi\u1ec1n l\u00e3i \u0111\u01b0\u1ee3c t\u00ednh th\u00eam 1 v\u00f2ng.
\n48 * 12.5 = 600k<\/p>\n
Tr\u00fang c\u1ea3 3 s\u1ed1 (t\u1ee9c v\u1ec1 c\u1ea3 3 c\u1eb7p) th\u00ec t\u00ednh ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c nh\u00e2n t\u1ef7 l\u1ec7 nh\u01b0 th\u01b0\u1eddng.
\n144 * 12.5 = 1800k<\/p>\n
<\/span>C\u00e1ch ch\u01a1i S\u1ed1 \u0111\u00e1 4 c\u00f3 ti\u1ec1n l\u1eddi th\u1ebf n\u00e0o?<\/h3>\nT\u01b0\u1eddng t\u1ef1 ch\u00fang ta c\u00f3 ti\u1ebfp \u0111\u00e1 l\u00f4 4 l\u00e0 ch\u1ecdn ra 4 con s\u1ed1 v\u00e0 ch\u00fang t\u1ea1o th\u00e0nh 6 c\u1eb7p s\u1ed1 kh\u00f4ng tr\u00f9ng l\u1eb7p. (6 v\u00f2ng)<\/p>\n
Ch\u01a1i s\u1ed1 \u0111\u00e1 4 con, ch\u00fang s\u1ebd t\u1ea1o th\u00e0nh 6 c\u1eb7p, ch\u1ec9 c\u1ea7n c\u00f3 1 c\u1eb7p (t\u1ee9c l\u00e0 2 s\u1ed1 trong t\u1ed5ng 4 s\u1ed1) v\u1ec1 th\u00ec anh em tr\u00fang s\u1ed1. Chia ra c\u00e1c tr\u01b0\u1eddng h\u1ee3p c\u1ee5 th\u1ec3 nh\u01b0 sau:<\/p>\n
Tr\u00fang 1 c\u1eb7p: ti\u1ec1n l\u00e3i t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 2.<\/p>\n
V\u1ec1 3 s\u1ed1 trong t\u1ed5ng 4 s\u1ed1: ti\u1ec1n l\u00e3i t\u00ednh nh\u01b0 tr\u00fang s\u1ed1 \u0111\u00e1 3<\/p>\n
V\u1ec1 c\u1ea3 4 s\u1ed1: t\u00ednh ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c nh\u00e2n t\u1ef7 l\u1ec7: 288 * 12.5 = 3600k<\/p>\n
Trong c\u00e1c tr\u01b0\u1eddng h\u1ee3p tr\u00ean, n\u1ebfu c\u00f3 1 s\u1ed1 v\u1ec1 2 nh\u00e1y th\u00ec t\u00ednh ti\u1ec1n l\u00e3i th\u00eam n\u1eeda v\u00f2ng. T\u1ee9c ti\u1ec1n x\u00e1c 1 \u0111i\u1ec3m nh\u00e2n v\u1edbi t\u1ef7 l\u1ec7 c\u01b0a \u0111\u00f4i.<\/p>\n
<\/p>\n
<\/span>Ti\u1ec1n l\u1eddi s\u1ed1 \u0111\u00e1 5 trong nhi\u1ec1u tr\u01b0\u1eddng h\u1ee3p<\/h3>\nS\u1ed1 \u0111\u00e1 5: ch\u1ecdn ra 5 con s\u1ed1 v\u00e0 ch\u00fang t\u1ea1o th\u00e0nh 10 c\u1eb7p s\u1ed1 kh\u00f4ng tr\u00f9ng l\u1eb7p. (10 v\u00f2ng)<\/p>\n
\u0110\u00e1nh s\u1ed1 \u0111\u00e1 5 c\u00f3 c\u00e1c tr\u01b0\u1eddng h\u1ee3p \u0103n ti\u1ec1n l\u00e3i t\u1eeb 2 cho t\u1edbi 4 s\u1ed1 tr\u00ean t\u1ed5ng 5 s\u1ed1 gi\u1ed1ng nh\u01b0 c\u00e1c tr\u01b0\u1eddng h\u1ee3p \u0111\u00e3 k\u1ec3 tr\u00ean.<\/p>\n
N\u1ebfu ra c\u1ea3 5 con s\u1ed1 th\u00ec ti\u1ec1n l\u00e3i b\u1eb1ng ti\u1ec1n x\u00e1c 10 v\u00f2ng nh\u00e2n t\u1ef7 l\u1ec7, s\u1ebd l\u00e0 12.5 * 480 = 6000k. Gi\u1ed1ng nh\u01b0 c\u00e1c tr\u01b0\u1eddng h\u1ee3p s\u1ed1 \u0111\u00e1 3 v\u00e0 4, n\u1ebfu c\u00f3 s\u1ed1 v\u1ec1 nhi\u1ec1u th\u00eam 1 nh\u00e1y th\u00ec t\u00ednh l\u00e0 \u0103n n\u1eeda v\u00f2ng. T\u1ee9c ti\u1ec1n x\u00e1c 1 v\u00f2ng nh\u00e2n t\u1ef7 l\u1ec7 c\u01b0a \u0111\u00f4i.<\/p>\n
<\/span>K\u1ebft lu\u1eadn<\/h2>\nNh\u00ecn chung, c\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 n\u00e0y r\u1ea5t c\u00f3 l\u1ee3i cho ng\u01b0\u1eddi ch\u01a1i l\u00f4 \u0111\u1ec1. Kh\u00e1 gi\u1ed1ng v\u1edbi \u0111\u00e1nh nhi\u1ec1u c\u00e1i l\u00f4 xi\u00ean 2, 3, 4 m\u1ed9t l\u00fac nh\u01b0ng ti\u1ec1n x\u00e1c v\u00e0 t\u1ef7 l\u1ec7 \u0103n th\u00ec c\u00f3 kh\u00e1c bi\u1ec7t.<\/p>\n
Anh em ch\u01a1i s\u1ed1 \u0111\u00e1 th\u00ec ch\u1ec9 c\u00f3 th\u1ec3 ch\u01a1i \u1edf mi\u1ec1n Nam. \u1ede mi\u1ec1n B\u1eafc kh\u00f4ng th\u1ea5y ph\u1ed5 bi\u1ebfn c\u00e1ch ch\u01a1i n\u00e0y. Ch\u01a1i \u0111\u00e0i mi\u1ec1n Nam r\u1ea5t kh\u00f3 v\u00ec c\u00f3 qu\u00e1 nhi\u1ec1u \u0111\u00e0i v\u00e0 kh\u00f3 soi c\u1ea7u b\u1eaft s\u1ed1. Tuy nhi\u00ean v\u1edbi c\u00e1ch \u0111\u00e1nh n\u00e0y, hy v\u1ecdng \u0111\u00e3 cho anh em th\u1ea5y \u0111\u01b0\u1ee3c m\u1ed9t l\u1ed1i ch\u01a1i l\u00f4 \u0111\u1ec1 m\u1edbi cho m\u00ecnh. B\u1ea3n th\u00e2n V\u0169 th\u1ea5y c\u00e1ch ch\u01a1i s\u1ed1 \u0111\u00e1 th\u1eadt s\u1ef1 h\u1eefu d\u1ee5ng. Do \u0111\u00f3 c\u0169ng mong anh em c\u00e2n nh\u1eafc ch\u01a1i c\u00e1ch n\u00e0y nhi\u1ec1u h\u01a1n.<\/p>\n